As requested here is the marking scheme for the writing paper.

Q1

Task Fulfilment

(critical thinking skills, answered the requirements of the question, clear introduction and overview linked stimulus, synthesise info, many accurate key features, good conclusion etc)

B6 : 18 -20

B5 : 17 - 15

B4 : 14 - 11

B3 : 10 - 7

B2 : 6 - 4

B1 : 3 - 0

Total: x/20

Language & Organisation

(Grammatical accuracy, vocabulary, relavant phrases, arrangement of report (intro, key features and conclusion), word count does not exceed 200 words (ignore 201 onwards) etc.)

B6 : 18 - 20

B5 : 17 -- 15

B4 : 14 - 11

B3 : 10 - 7

B2 : 6 - 4

B1 : 3 - 0

Total: y/20

So for question 1, x + y = a/40

Q2

Same as above, Task Fulfillment (x/30) + Language & Organisation (y/30) = b/60

B6 : 30 - 26

B5 : 25 - 21

B4 : 20 - 16

B3 : 15 - 11

B2 : 10 - 6

B1 : 5 - 0

TOTAL FOR WRITING PAPER Q1 (a) + Q2 (b) = z/100

CONVERT TO 30% weightage

90/300 = z x 0.9

example: 50 x 0.9 = 45 marks from maximum 90 for the writing component.

Does anyone have any issues about how to calculate the marks for muet?

It's a bit tricky but here are the breakdowns.

Listening : students' mark x 45 / 20 = i

Speaking : students' mark x 45 / 54 = ii

Reading : students' mark x 120 / 45 = iii

Writing : students' mark x 90 /100 = ix

TOTAL MUET MARKS : i + ii + iii + iv = Z/300

B6 : 260 - 300

B5 : 220 - 259

B4 : 180 - 219

B3 : 140 - 179

B2 : 100 - 139

B1 : 0 -99

Ok.. i know what you're dying to know now. haha.. how do we calculate the speaking marks right. This is even more complicated at the real exam level. Here goes.

Task A

a) Task fulfilment (relevant answers) maximum 18 marks

b) Language max 18 marks

c) Communicative ability (gestures, eye contact, convincing style, confidence, fluency etc) max 18

B6 : 16 - 18

B5 : 13 - 15

B4 : 10 - 12

B3 : 7 - 9

B2 : 4 - 6

B1 : 0 - 3

So task A, a + b + c = x/54

Task B is exactly the same breakdown of marks.. max 18 each category

a) Task fulfilment (understands topic, relevant response)

b) Language

c) Communicative ability (fuency, interact confidently, manage a discussion, displays initative etc.)

So task B, a + b + c = x/54

TO GET THE TOTAL U HAVE TO AVERAGE TASK A & TASK B = total x/54

In the actual exam, it gets extremely complicated cos after every group the two examiners must have a discussion about the performance of each candidate and standardised their marks. so there will be adjustment of marks on the spot according to performance and discussion of examiners, and they will double check if they agree with the marks by ranking the four candidates. when they are satisfied with the marks awarded, then the examiners will call in the next group. quite a tedious process if you ask me, but very necessary.

HOWEVER,

for school exams. I use an 18 point system for Task A & B, then I average the marks and convert to 54 by multiplying by 3. Youc can use this system if you like or simply ignore it if you find it is not accurate enough.

low - mid - high

18 - 17 -16 = B6

13 - 14 - 15 = B5

10 - 11 - 12 = B4

7 - 8 - 9 = B3

4 - 5 - 6 = B2

1 - 2 - 3 = B1

I find this to be the best method cos it's not as complicated and as an examiner you always have to consider if the candidate is low, mid or high band 1, 2, 3, 4, 5 or 6.

CONGRATULATIONS if you have understood everything I have written thus far. Any questions? Please feel free to ask.

## Tuesday, September 28, 2010

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